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First solution in Speedy category for Boolean Algebra by pytonio
op = {"conjunction":"x and y", "disjunction":"x or y", "implication":"not x or y", "exclusive":"x != y", "equivalence":"x == y"}
def boolean(x, y, operation):
return eval(op[operation])
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Feb. 26, 2015
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