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quite speed solution in Speedy category for Boolean Algebra by lsk45
OPERATION_NAMES = {"conjunction": 'x and y', "disjunction": 'x or y', "implication": 'not x or y', "exclusive": 'x!=y', "equivalence": 'x==y'}
def boolean(x, y, operation):
if eval(OPERATION_NAMES[operation]):
return 1
return 0
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
April 11, 2015
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