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First solution in Clear category for Boolean Algebra by jonmor75
def boolean(x, y, operation):
if operation == "conjunction":
return (x and y) # x ∧ y
if operation == "disjunction":
return (x or y) # x ∨ y
if operation == "implication":
return not x or y # ¬ x ∨ y
if operation == "exclusive":
return (x or y) and not (x and y) # xor: (x ∨ y)∧ ¬ (x ∧ y)
if operation == "equivalence":
return x == y # ¬ (x ⊕ y)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
May 31, 2016