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First solution in Clear category for Boolean Algebra by Wojtas1411
OPERATION_NAMES = ["conjunction", "disjunction", "implication", "exclusive", "equivalence"]
def boolean(x, y, operation):
x=bool(x)
y=bool(y)
if OPERATION_NAMES.index(operation)==0:
return (x and y)
elif OPERATION_NAMES.index(operation)==1:
return (x or y)
elif OPERATION_NAMES.index(operation)==2:
return (not x or y)
elif OPERATION_NAMES.index(operation)==3:
return ((x or y) and not(x and y))
elif OPERATION_NAMES.index(operation)==4:
return not ((x or y) and not(x and y))
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Nov. 10, 2016