Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Arithmetic solution in Creative category for Boolean Algebra by Sim0000
OPERATION_NAMES = ("conjunction", "disjunction", "implication", "exclusive", "equivalence")
def boolean(x, y, operation):
return (x*y, x+y>0, x<=y, x!=y, x==y)[OPERATION_NAMES.index(operation)]
# logic : arithmetic
# x&y : x*y
# x|y : x+y>0
# (1^x)|y : x<=y
# x^y : x!=y
# x^y^1 : x==y
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Sept. 3, 2014
Comments: