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dict with lambda solution in Clear category for Boolean Algebra by M157q
def boolean(x, y, op_name):
op = {
"conjunction": lambda x, y: x and y,
"disjunction": lambda x, y: x or y,
"implication": lambda x, y: not x or y,
"exclusive": lambda x, y: x ^ y,
"equivalence": lambda x, y: x == y
}
return op[op_name](x, y)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Nov. 5, 2015
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