Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
keiです、ども(`・ω・´) solution in Clear category for Bigger Price by s.keigo.11235813
def bigger_price(limit: int, data: list) -> list:
"""
TOP most expensive goods
"""
# your code here
length = len(data)
sort_data = []
for i in range(length):
for j in range(i, length):
if data[j]['price'] > data[i]['price']:
high = data[i]
data[i] = data[j]
data[j] = high
for i in range(limit):
sort_data.append(data[i])
return sort_data
# another pattern
# return sorted(data, key=lambda x: x['price'], reverse=True)[:limit]
if __name__ == '__main__':
from pprint import pprint
print('Example:')
pprint(bigger_price(2, [
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1}
]))
# These "asserts" using for self-checking and not for auto-testing
assert bigger_price(2, [
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1}
]) == [
{"name": "wine", "price": 138},
{"name": "bread", "price": 100}
], "First"
assert bigger_price(1, [
{"name": "pen", "price": 5},
{"name": "whiteboard", "price": 170}
]) == [{"name": "whiteboard", "price": 170}], "Second"
print('Done! Looks like it is fine. Go and check it')
July 29, 2021
Comments: