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Sorted to find max solution in Clear category for Bigger Price by Striga
def bigger_price(limit: int, data: list) -> list:
return sorted(data, key = lambda x: x['price'], reverse = True)[:limit]
if __name__ == '__main__':
assert bigger_price(2, [
{"name": "bread", "price": 100},
{"name": "wine", "price": 138},
{"name": "meat", "price": 15},
{"name": "water", "price": 1}
]) == [
{"name": "wine", "price": 138},
{"name": "bread", "price": 100}
], "First"
assert bigger_price(1, [
{"name": "pen", "price": 5},
{"name": "whiteboard", "price": 170}
]) == [{"name": "whiteboard", "price": 170}], "Second"
Oct. 3, 2020