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regexp solution in Clear category for Backward Each Word by perimeter
def backward_string_by_word(text: str) -> str:
# your code here
import re
pat = re.compile(r'([\S]+|[\s]+)')
words = pat.finditer(text)
return ''.join(word.group()[::-1] for word in words)
if __name__ == '__main__':
print("Example:")
print(backward_string_by_word(''))
# These "asserts" are used for self-checking and not for an auto-testing
assert backward_string_by_word('') == ''
assert backward_string_by_word('hello world') == 'olleh dlrow'
assert backward_string_by_word('world') == 'dlrow'
assert backward_string_by_word('hello world') == 'olleh dlrow'
assert backward_string_by_word('welcome to a game') == 'emoclew ot a emag'
print("Coding complete? Click 'Check' to earn cool rewards!")
Oct. 22, 2021
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