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or len(set(password)) < 3 solution in Creative category for Acceptable Password VI by SHAKHRUKHIRGASHEV
def is_acceptable_password(password: str) -> bool:
import re
pat = r'\d'
if 'PASSWORD' in password:
return False
elif 'password' in password:
return False
if len(password) >=10 and len(set(password)) > 3:
return True
if len(password) <= 6 or len(re.findall(pat, password)) == 0 or all([i.isdigit() for i in password]) or len(set(password)) < 3:
return False
return True
June 11, 2022
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