Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Acceptable Password V by vnkvstnk
def is_acceptable_password(a):
return "password" not in a.lower() \
and (len(a) > 9 or 0 < sum(map(str.isdigit, a)) < len(a) > 6)
May 1, 2020
Comments: