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First solution in Clear category for Acceptable Password V by raycdg
def is_acceptable_password(password: str) -> bool:
if password.upper().find('PASSWORD') > -1:
return False
return (len(password) > 6 and \
any(map(lambda x: x.isdigit(), list(password))) and \
not password.isdigit()) or \
(len(password) > 9)
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
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Dec. 7, 2021
