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module re and string lower solution in Clear category for Acceptable Password V by Yrix90
import re
def is_acceptable_password(a):
if (len(a) > 6 and re.search(r'\d', a) and re.search(r'\D', a) or len(a) > 9) and ('password' not in a.lower()):
return True
else:
return False
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
Feb. 24, 2021
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