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First solution in Clear category for Acceptable Password V by MBM_1607
def is_acceptable_password(password: str) -> bool:
return ((len(password) > 6 \
and any(map(str.isdigit, password))) \
and not all(map(str.isdigit, password)) \
or len(password) >= 10) \
and not "password" in password.lower()
April 3, 2020
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