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First solution in Speedy category for Acceptable Password V by Liam_Lau
# Taken from mission Acceptable Password IV
import re
def is_acceptable_password(password):
# your code here
print(len(password))
tmp = (len(re.findall('password',password.lower()))<=0) and (len(password)>6)and ((len(password)>9 or (len(re.findall('[[\d]', password))>0 and len(re.findall('[[\D]', password))>0)))
return tmp
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
June 11, 2020