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First solution in Clear category for Acceptable Password IV by arek121281
# Taken from mission Acceptable Password III
def is_acceptable_password(password: str) -> bool:
# your code here
return (len(password) > 6 and any([i.isnumeric() for i in password]) and not all([i.isnumeric() for i in password])) or len(password)>8
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
March 14, 2021