one line, one or, no and clear solution for Acceptable Password IV by Kosya - python coding challenges

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one line, one or, no and solution in Clear category for Acceptable Password IV by Kosya

# Taken from mission Acceptable Password III

# Taken from mission Acceptable Password II

# Taken from mission Acceptable Password I

def is_acceptable_password(password: str) -> bool:
    # your code here
    return 6 < len(password) > sum([i.isdigit() for i in password]) > 0 or len(password) > 9




if __name__ == "__main__":
    # These "asserts" are used for self-checking and not for an auto-testing
    assert is_acceptable_password("short") == False
    assert is_acceptable_password("short54") == True
    assert is_acceptable_password("muchlonger") == True
    assert is_acceptable_password("ashort") == False
    assert is_acceptable_password("muchlonger5") == True
    assert is_acceptable_password("sh5") == False
    assert is_acceptable_password("1234567") == False
    assert is_acceptable_password("12345678910") == True
    print("Coding complete? Click 'Check' to earn cool rewards!")

Aug. 31, 2021

Comments:

amandel on Sept. 11, 2022, 12:05 p.m.
<p>Straightforward solution, no frills. Using any instead of sum would have been nicer.</p>

Strings Theory

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