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fail asap solution in Speedy category for Acceptable Password IV by Alexey.K.
import re
def is_acceptable_password(password: str) -> bool:
if password.isdigit() and len(password)<9: return False
if len(password)<=6: return False
if not bool(re.search(r'\d', password)) and len(password)<9: return False
return True
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
March 18, 2021