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First solution in Clear category for Acceptable Password III by bartholomewbrokka
def is_acceptable_password(password: str) -> bool:
if len(password) < 7:
return False
digit = False
non_digit = False
for x in password:
if x.isdigit():
digit = True
else:
non_digit = True
return digit and non_digit
Jan. 29, 2021
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