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"Acceptable Password III" solution in Uncategorized category for Acceptable Password III by Mateusz_Wryszcz
# Taken from mission Acceptable Password II
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
if len(password) > 6 and any(i.isdigit() for i in password) and password.islower():
return True
else:
return False
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
print("The mission is done! Click 'Check Solution' to earn rewards!")
Dec. 6, 2022
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