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One liner solution in Clear category for Acceptable Password II by sushant6195
def is_acceptable_password(password:str) -> bool:
return True if any([x.isdigit() for x in list(password)]) and len(password) > 5 else False
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
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March 28, 2022