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First solution in Clear category for Acceptable Password II by mennadiego
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
contain_digit = False
for letter in password:
if letter.isdigit():
contain_digit = True
return len(password) > 6 and contain_digit
print("Example:")
print(is_acceptable_password("short"))
# These "asserts" are used for self-checking
print("The mission is done! Click 'Check Solution' to earn rewards!")
Aug. 5, 2023