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Len & count digits solution in Clear category for Acceptable Password II by Striga
def is_acceptable_password(password: str) -> bool:
return len(password) > 6 and len([x for x in password if x.isdigit()]) > 0
if __name__ == '__main__':
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
Oct. 12, 2020