check result error.
I would like to give some feedback about ...
From: https://checkio.org/mission/flatten-list/solve/
HTTP_USER_AGENT:
Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/51.0.2704.103 Safari/537.36
Hi. My code looks like right, but i cant pass "check result". Or its my bug? [spoiler]
b =[] def flat_list(array): for a in array: if type(a) is list: flat_list(a) else: b.append(a) return b
thx for checkio.org ))
Jacob