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How to get the value (1,3) in checkio() ?
f = lambda x,y: x+y g = lambda x,y: (x
2 - y
2)/(x-y) checkio(f,g)(1,3) == (4,"same")
task.comp_funcs
Created: April 10, 2016, 4:16 p.m.
Updated: April 10, 2016, 5:24 p.m.
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rushpixy
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