• about one line drawing


I would like to give some feedback about ...

From: http://www.checkio.org/mission/one-line-drawing/solve/


Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/31.0.1650.63 Safari/537.36

mydict={} mypoints=[] mylevel = 0

def inPaths( p1, p2, data): for item in data: if p1[0] == item[0] and p1[1] == item[1] and p2[0] == item[2] and p2[1] == item[3]: return True if p1[0] == item[2] and p1[1] == item[3] and p2[0] == item[0] and p2[1] == item[1]: return True return False

def inCurPath( p1, p2, curpath): for i in range(0, len(curpath)-1): if p1[0] == curpath[i][0] and p1[1] == curpath[i][1] and p2[0] == curpath[i+1][0] and p2[1] == curpath[i+1][1]: return True if p2[0] == curpath[i][0] and p2[1] == curpath[i][1] and p1[0] == curpath[i+1][0] and p1[1] == curpath[i+1][1]: return True return False

def findNextPoint( curpath ,data): global mydict if curpath[0] not in mydict: mydict[ curpath[0] ] = curpath

path = mydict[ curpath[0] ]
#save longer path
if len(path) < len(curpath):
    mydict[ curpath[0] ] = curpath

for item in mypoints:
    if inPaths( curpath[-1], item,data)== True and inCurPath( curpath[-1],item, curpath) == False:
        #print( "new item:", item, "curpath=",curpath)
        curpath.append( item )
        findNextPoint(curpath, data)
if len(curpath) == len( data )+1:
    mydict[ curpath[0] ] = curpath
    return True
return False

def mydraw(data): global mydict global mypoints mydict={} mypoints=[] for item in data: line = list(item)
point1 = (line[0],line[1]) point2 = (line[2],line[3]) if point1 not in mypoints: mypoints.append( point1 ) if point2 not in mypoints: mypoints.append( point2 ) #print( "mypoints",mypoints) for item in mypoints: curpath = [ item ]
findNextPoint(curpath, data)

#print( "mydict",mydict)
result =[]
for item in mypoints:
    if len( mydict[item] ) == len(data)+1:
        print( mydict[item]  )
        return mydict[item]
return []

def draw(data): mydraw({(1,1,2,2),(2,1,2,2),(2,1,3,2),(2,1,3,1),(1,1,0,2),(1,1,0,0),(3,2,3,1),(0,0,0,2)}) return mydraw(data)