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def checkio(arg):

def checkio(arg): byte = r'(?:2(?:5[0-5]|[0-4]\d)|1\d\d|[1-9]\d|[1-9])' return r'\b' + r'.'.join([byte]*4)

Created: Sept. 23, 2010, 5:50 a.m.
Updated: Sept. 30, 2013, 1:46 p.m.
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