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100 consist of 3 digits [1

100 consist of 3 digits [1,0,0] then the result is 1!+0!+0! = 1 + 1 + 1 = 3. The same for 123 -> [1,2,3] = 1! + 2! + 3! = 1 + 12 + 12*3 = 1 + 2 + 6 = 9

Created: April 6, 2011, 11:20 a.m.
Updated: Sept. 30, 2013, 1:46 p.m.
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artemrudenko