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Fizz Buzz

def checkio(number): if 0<number<=1000: if number%15==0: print("Fizz Buzz") elif number%3==0: print("Fizz") elif number%5==0: print("Buzz") else: return str(number) else: print("Need >0 and <=1000")

Created: June 5, 2015, 9:09 a.m.
Updated: June 8, 2015, 5:35 p.m.
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golovnich_dima