Check if a value is in the next index
def goes_after(word: str, first: str, second: str) -> bool: the_list = list(word) if len(the_list) == 0: return False elif first in the_list[0] and second in the_list[1]: return True else: return False
This is a bit of code to check if the "first" and the "second" is in the [0] position and [1] position in a list.
Now im trying to find a solution to check if the "second" is the next index after the "first".
i was thinking to add something like:
if second == the_list[first + 1]: return True
but dont really find a solution to write this code without getting error messages. But i think this could be a solution to my problem.