• Acceptable password II "muchlonger5" case

 

Hello, I'm using this function to solve the challenge but check fails at Test4/4

def is_acceptable_password(password: str) -> bool:

    for char in password:
        if char.isdigit():
            return len(password) > 6
    return False

Moreover even with this trick

def is_acceptable_password(password: str) -> bool:
    return True

I have the same response from checker with "Your result: False".