Remove all before

hi, any suggestions to display the entire list when not finding the first digit of the new list.

from typing import Iterable
    def remove_all_before(items: list, border: int) -> Iterable:
        z=[]
        y=[]
        v=[]
        for i in range(len(items)):
            if items[i] >= border:
                y.append(items[i])   #<==new list
            else:
                z.append(items[i])   #<copy orignal list

    if y != v :
        return y
    else:
        return z
if __name__ == '__main__':
    print("Example:")
    print(list(remove_all_before([1, 2, 3, 4, 5], 3)))

    # These "asserts" are used for self-checking and not for an auto-testing
    assert list(remove_all_before([1, 2, 3, 4, 5], 3)) == [3, 4, 5]
    assert list(remove_all_before([1, 1, 2, 2, 3, 3], 2)) == [2, 2, 3, 3]
    assert list(remove_all_before([1, 1, 2, 4, 2, 3, 4], 2)) == [2, 4, 2, 3, 4]
    assert list(remove_all_before([1, 1, 5, 6, 7], 2)) == [1, 1, 5, 6, 7]  #<--------------<----------<my error
    assert list(remove_all_before([], 0)) == []
    assert list(remove_all_before([7, 7, 7, 7, 7, 7, 7, 7, 7], 7)) == [7, 7, 7, 7, 7, 7, 7, 7, 7]