popular-word resolution pass for pass

def popular_words(text: str, words: list) -> dict: # your code here text = text.lower().replace('\n', ' ').split(' ')

palabras = {}
for w in words:
    if w in text:
        palabras[w] = (text.count(w))
    else:
        palabras[w] = (text.count(w))

return palabras