Problem: You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.
Let's look at a few examples:
- array = [1, 2, 3, 4] and N = 2, then the result is 32 == 9;
- array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.
Can anyone help me figure out why this doesn't work?
def index_power(array, n):
for i in array:
if array.index(i) == n:
return i**n
elif n > len(array)-1:
return -1
Created at: July 9, 2019, 10:53 p.m.; Updated at: July 10, 2019, 3:36 a.m.