Sort Array by Element frequency
def frequency_sort(items):
a = []
for i in items:
for j in list(range(len(items))):
if i not in a:
for n in list(range(items.count(i))):
a.append(i)
return a
if __name__ == '__main__':
print("Example:")
print(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
Run Output:
Example:
[4, 4, 4, 4, 6, 6, 2, 2]
Coding complete? Click 'Check' to earn cool rewards!
Check Results:
Your result:[4,4,4,4,6,6,2,2,2]
Right result:[4,4,4,4,2,2,2,6,6] HOW COME THIS IS THE RIGHT ANSWER IF 2 APPEARS AFTER 6??????????
Fail:frequency_sort([4,6,2,2,2,6,4,4,4])
I'm afraid something's wrong... and it's not my code... he he he
What should I do to collect my points and move on?
HELP!
Created at: 2019/05/30 20:06; Updated at: 2019/05/31 16:05