def checkio(data):
#print ('input', data)
for i in data:
#print ('i', i)
if data.count(i) == 1: data.remove(i); #print ('count=', data.count(i), '-del')
#print ('output', data)
return data
This code run in strange ways: some times cycle for not run properly and drop some counts.
Here output for this code:
>>>checkio([1,2,3,2,1])
i 1
i 2
i 3
count= 0 -del
i 1
<<< [1, 2, 2, 1] # ALL OK, NO BUG
>>>checkio([1,2,3,4,5])
i 1
count= 0 -del
i 3
count= 0 -del
i 5
count= 0 -del
<<< [2, 4] #??? BUG on even counts
>>>checkio([1,2,3,4,5,6,1])
i 1
i 2
count= 0 -del
i 4
count= 0 -del
i 6
count= 0 -del
<<< [1, 3, 5, 1] #??? BUG odd counts
From: https://py.checkio.org/mission/non-unique-elements/solve/
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Created at: 2016/10/04 23:36; Updated at: 2016/10/05 19:19