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/vote/forum/post/10154/up/1/
/vote/forum/post/10154/down/1/
/vote/forum/post/10154/clear/1/
Probably just what everyone else did...
def checkio: return [x for x in d if d.count(x)>1]
task.non-unique-elements
Created: Sept. 17, 2016, 11:15 p.m.
Updated: Oct. 8, 2016, 3:30 p.m.
0
4
joe056_c97bd898c0c0422f82fb902