You have to write a function that receives a "today" date and a dictionary of family birthdates, and for the person(s) whose birthday is next (today or later), return the number of days between "today" and that birthday, and the age they will be.
Note about leap days: If someone is born on February 29th, then he or she will celebrate birthdays on March 1st when necessary.
Input: Two arguments:
- a tuple of three integers...
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CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=py config --key=
Sync solutions into your local folder
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin --ff
checkio install-plugin --chromium