You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.

Let's look at a few examples:

- array = [1, 2, 3, 4] and N = 2, then the result is 3^{2} == 9;

- array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.

**Input: ** Two arguments. An array as a list of integers and a number as a integer.

**Output: ** The result as an integer.

**Example:**

index_power([1, 2, 3, 4], 2) == 9 index_power([1, 3, 10, 100], 3) == 1000000 index_power([0, 1], 0) == 1 index_power([1, 2], 3) == -1

**How it is used: **
This mission teaches you how to use basic arrays and indexes when combined with simple mathematics.

**Precondition:**
0 < len(array) ≤ 10

0 ≤ N

all(0 ≤ x ≤ 100 for x in array)