I start to feed one of the pigeons. A minute later two more fly by and a minute after that another 3. Then 4, and so on (Ex: 1+2+3+4+...). One portion of food lasts a pigeon for a minute, but in case there's not enough food for all the birds, the pigeons who arrived first ate first. Pigeons are hungry animals and eat without knowing when to stop. If I have N portions of bird feed, how many pigeons will be fed with at least one portion of wheat?
Input: A quantity of portions wheat as a positive integer.
Output: The number of fed pigeons as an integer.
checkio(1) == 1 checkio(2) == 1 checkio(5) == 3 checkio(10) == 6
How it is used: This task illustrates how we can model various situations. Of course, the model has a limited approximation, but often-times we don't need a perfect model.
Precondition: 0 < N < 10 5 .
CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=py config --key=
Sync solutions into your local folder
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin --ff
checkio install-plugin --chromium