Determine The Trajectory Of Frogs And Make Sure Your Code Doesn't Stink

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Let's find out if frogs will intersect and learn how to make your code less "stinky".

💡TIP

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🏁MISSION

Frogs Collision by freeman_lex -

In the vast expanse of an infinite two-dimensional grid, two adventurous frogs embark on their hopping journey. Each frog, characterized by a unique 4-tuple, sets forth with determination. Their positions at time t=0 and constant directional vectors propel them forward through discrete time steps. As they leap across the grid, the question arises: will their paths intertwine? The challenge beckons for a solution to determine the precise moment when both frogs, frog1 and frog2, synchronize their hops onto the same square. Should fate decree their paths never to converge, the function shall gracefully return None, leaving their trajectories to wander in parallel, never to intersect.

frogs_collision((0, 0, 0, 2), (0, 10, 0, 1)) == 10
frogs_collision((10, 10, -1, 0), (0, 1, 0, 1)) == None

📖ARTICLE

Fix Python Code Smells with These Best Practices -

By finding and refactoring this stinky code, we can make our codebase more maintainable, readable, and scalable. This will make it easier for us to add new features, fix bugs, and collaborate with other developers.

👩‍💻CODE SHOT

How do you think, what the following code does?

?????? = lambda num: len(__import__("re").search('0*$', str(num)).group(0))

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