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Xs and Os Referee solution in Clear category for Xs and Os Referee by joskar1999
def checkio(game_result):
tab = []
for i in game_result:
tab.append(i)
if (tab[0][0] == 'X' and tab[0][1] == 'X' and tab[0][2] == 'X'): return 'X'
elif (tab[0][0] == 'O' and tab[0][1] == 'O' and tab[0][2] == 'O'): return 'O'
if (tab[1][0] == 'X' and tab[1][1] == 'X' and tab[1][2] == 'X'): return 'X'
elif (tab[1][0] == 'O' and tab[1][1] == 'O' and tab[1][2] == 'O'): return 'O'
if (tab[2][0] == 'X' and tab[2][1] == 'X' and tab[2][2] == 'X'): return 'X'
elif (tab[2][0] == 'O' and tab[2][1] == 'O' and tab[2][2] == 'O'): return 'O'
if (tab[0][0] == 'X' and tab[1][0] == 'X' and tab[2][0] == 'X'): return 'X'
elif (tab[0][0] == 'O' and tab[1][0] == 'O' and tab[2][0] == 'O'): return 'O'
if (tab[0][1] == 'X' and tab[1][1] == 'X' and tab[2][1] == 'X'): return 'X'
elif (tab[0][1] == 'O' and tab[1][1] == 'O' and tab[2][1] == 'O'): return 'O'
if (tab[0][2] == 'X' and tab[1][2] == 'X' and tab[2][2] == 'X'): return 'X'
elif (tab[0][2] == 'O' and tab[1][2] == 'O' and tab[2][2] == 'O'): return 'O'
if (tab[0][0] == 'X' and tab[1][1] == 'X' and tab[2][2] == 'X'): return 'X'
elif (tab[0][0] == 'O' and tab[1][1] == 'O' and tab[2][2] == 'O'): return 'O'
if (tab[0][2] == 'X' and tab[1][1] == 'X' and tab[2][0] == 'X'): return 'X'
elif (tab[0][2] == 'O' and tab[1][1] == 'O' and tab[2][0] == 'O'): return 'O'
return 'D'
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
"X.O",
"XX.",
"XOO"]) == "X", "Xs wins"
assert checkio([
"OO.",
"XOX",
"XOX"]) == "O", "Os wins"
assert checkio([
"OOX",
"XXO",
"OXX"]) == "D", "Draw"
assert checkio([
"O.X",
"XX.",
"XOO"]) == "X", "Xs wins again"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Oct. 21, 2017
