str.join(iterable) clear solution for Xs and Os Referee by David_Jones - python coding challenges

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str.join(iterable) solution in Clear category for Xs and Os Referee by David_Jones

def checkio(game_result):
    lines = game_result
    game_result = ''.join(game_result)
    lines += [game_result[i::3] for i in range(3)]
    lines += [game_result[0::4], game_result[2:8:2]]
    for ch in 'OX':
        if ch * 3 in lines:
            return ch
    return 'D'

June 15, 2019

Comments:

chesse20 on July 20, 2019, 5:01 a.m.
please explain this its not clear to me at all

David_Jones on July 20, 2019, 10:58 a.m.
<pre class='brush: python'>def checkio(game_result): lines = game_result # rows game_result = ''.join(game_result) lines += [game_result[i::3] for i in range(3)] # + columns lines += [game_result[0::4], game_result[2:8:2]] # + diagonals for ch in 'OX': if ch * 3 in lines: # check if there's XXX/OOO in a row anywhere return ch return 'D' </pre>

chesse20 on July 21, 2019, 5:07 a.m.
oh i looked up the double colons, so [i::3] gets one element, and then the elements three after it; so its get elements 0 3 and 6 which is column one and then the other two columns. and the first diagonal gets the 0th element and then every 4 elements after making the left top to bottom left diagonal, and then game_result[2:8:2] gets the 3nd 5th 7th and element, which makes the top right to bottom left diagonal.

atikin88 on Feb. 18, 2020, 1:43 p.m.
Realy short and clear, i like it!

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