sorted == words clear solution for Words Order by flpo - python coding challenges

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sorted == words solution in Clear category for Words Order by flpo

def words_order(text, words):
    text_words = {w for w in text.split() if w in words}
    return list(sorted(text_words, key=text.index)) == words

May 6, 2020

Comments:

VincentDog on Nov. 2, 2020, 1:12 p.m.
I don't understand the syntax of the second line: {w for w in text.split() if w in words} Can you advise where I can read more of it? Thanks

VincentDog on Nov. 2, 2020, 1:18 p.m.
does it return a set of items (w) if w in both text.split() and words?

flpo on Nov. 2, 2020, 1:41 p.m.
Yes, actually it iterates over all `w` in `text.split()` and add `w` to the resulting set if `w in words`. The syntax is called comprehension, it can be used for lists/sets/dicts and generators. <a href="https://docs.python.org/3/tutorial/datastructures.html#list-comprehensions">Here</a> you can find the list comprehensions documentation. Hope this helps!

VincentDog on Nov. 2, 2020, 7:18 p.m.
Helped a lot, thanks for such a comprehensive answer:)

TrexxaByte on Jan. 29, 2022, 7:39 a.m.
That line, I THINK, is taking the text, putting it into list form (like the words) and checking to see if each word in the "words" list is actually present and IN the text... which wouldn't work unless it was put into a list. Because of the curveball they put in... where the words are ['wo', 'rld'] if text.split() wasn't done, it would return True, which is wrong.

jiaoxueyuan1108 on Dec. 3, 2020, 1:45 p.m.
key=text.index can somebody tell me what this does?

kunkka71 on Dec. 11, 2020, 6:20 a.m.
It means to sort the items based on their index in 'text'. Consider the following example: <pre class='brush: python'>words = ['x', 'z', 'a'] text = 'zax' </pre> If I want to sort the items in the 'words' list, based on their index in 'text', I'll sort it: <pre class='brush: python'>sorted(words, key = text.index) </pre> and it will result to <pre class='brush: python'>['z', 'a', 'x'] </pre>

captainmagellan on Dec. 15, 2020, 6:08 p.m.
This is really cool, thanks for the explanation!

FieldOfSnow on June 13, 2021, 7:47 a.m.
Woah! Super helpful.

TrexxaByte on Jan. 29, 2022, 7:48 a.m.
Tells the 'sorted()' function HOW to sort. Optional keyword argument.

bartholomewbrokka on Jan. 21, 2021, 11:58 p.m.
Did you use sorted() to sort this set of words intentionally? I think you could assign a list to text_words at once. <pre class='brush: python'>text_words = [w for w in text.split() if w in words] </pre>

natter1 on April 5, 2021, 11:23 a.m.
I think the set is because of: <ul> <li>two words in the given list are the same - your function should return False;</li> </ul> For a list, an additional check would be neccessary. <pre class='brush: python'>def words_order(text, words): return words == [w for w in text.split() if w in words and words.count(w) < 2] </pre>

rhodeus208 on Aug. 9, 2021, 2:15 a.m.
I didn't know the fact that we could eliminate all the blanks and split a text by text.split(). I learned this is different from text.split(' ').The latter can't eliminate every blank. And the key in sorted part is amazing. "key=text.index"

madelinejiang on Sept. 21, 2021, 7:31 p.m.
This should return False if there are duplicates in the words acc to the problem statement

TrexxaByte on Jan. 29, 2022, 7:46 a.m.
Doesn't this work without the list() around it? like... <pre class='brush: python'>return sorted(text_words, key=text.index) == words </pre> It seems to...

H0r4c3 on June 25, 2022, 6:54 p.m.
Great! Short and clear!

U.V on Sept. 14, 2022, 8:14 a.m.
This is PYTHONIC code. It's really short and clear!

jakubbortlik on Nov. 15, 2022, 12:41 p.m.
This solution fails in cases like `assert words_order("heretic world here", ["world", "here"]) == True` because `text.index("here")` equals `0`. I used a similar approach with `sorted` but used indexes in `text` split to a list. But the <a href="https://py.checkio.org/mission/words-order/publications/jakubbortlik/python-3/iterate-over-text-once-then-compare-lists/?ordering=most_voted&filtering=all">solution</a> turned out to be a little obscure so I placed in the "creative" section. The checks for this task are incomplete (my own solution with `re` passed as well even if it was faulty.

vvm70 on Nov. 26, 2022, 2:58 p.m.
You should write your comment <a href="https://py.checkio.org/forum/post/13917/new-mission-words-order/">here</a> Maybe the creator will fix it

walmas on April 15, 2024, 9:08 p.m.
Okay, the key for sorted is incredible. Very useful.

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