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Check sorted list of indexes solution in Uncategorized category for Words Order by akamus
def words_order(text: str, words: list) -> bool:
index_list = [text.find(word) for word in words if word in text.split()]
return True if index_list == sorted(index_list) and len(words) == len(set(index_list)) else False
if __name__ == '__main__':
print("Example:")
print(words_order('hi world im here', ['world', 'here']))
# These "asserts" are used for self-checking and not for an auto-testing
assert words_order('hi world im here', ['world', 'here']) == True
assert words_order('hi world im here', ['here', 'world']) == False
assert words_order('hi world im here', ['world']) == True
assert words_order('hi world im here',
['world', 'here', 'hi']) == False
assert words_order('hi world im here',
['world', 'im', 'here']) == True
assert words_order('hi world im here',
['world', 'hi', 'here']) == False
assert words_order('hi world im here', ['world', 'world']) == False
assert words_order('hi world im here',
['country', 'world']) == False
assert words_order('hi world im here', ['wo', 'rld']) == False
assert words_order('', ['world', 'here']) == False
print("Coding complete? Click 'Check' to earn cool rewards!")
June 15, 2020
