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Using timedelta class, weekday() solution in Clear category for Weekend Counter by H0r4c3
from datetime import date, timedelta
def checkio(from_date, to_date):
"""
Count the days of rest
"""
diff = to_date - from_date
days_list = [(from_date + timedelta(days=i)).weekday() for i in range(diff.days + 1) if (from_date + timedelta(days=i)).weekday() in [5, 6]]
return len(days_list)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(date(2013, 9, 18), date(2013, 9, 23)) == 2, "1st example"
assert checkio(date(2013, 1, 1), date(2013, 2, 1)) == 8, "2nd example"
assert checkio(date(2013, 2, 2), date(2013, 2, 3)) == 2, "3rd example"
Feb. 13, 2022
