Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Verify Anagrams by HubertDolny
# migrated from python 2.7
def verify_anagrams(first_word, second_word):
first_word=str(first_word)
second_word=str(second_word)
first_word=first_word.lower()
second_word=second_word.lower()
first_word=first_word.replace(" ", "")
second_word=second_word.replace(" ", "")
list1=[]
list2=[]
for i in range(0,(len(first_word))):
list1.append(first_word[i])
for i in range(0,(len(second_word))):
list2.append(second_word[i])
if len(list1)!=len(list2):
return False
for i in list1[:]:
if i in list2[:]:
list1.remove(i)
list2.remove(i)
print(( len(list1)))
print((len(list2)))
if len(list1)>0 and len(list2)>0:
return False
return True
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(verify_anagrams("a", "z"), bool), "Boolean!"
assert verify_anagrams("Programming", "Gram Ring Mop") == True, "Gram of code"
assert verify_anagrams("Hello", "Ole Oh") == False, "Hello! Ole Oh!"
assert verify_anagrams("Kyoto", "Tokyo") == True, "The global warming crisis of 3002"
Oct. 23, 2016
