Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Verify Anagrams by Andreas_Strus
def verify_anagrams(first_word, second_word):
s = ""
first_word = first_word.split()
second_word = second_word.split()
first_word = s.join(first_word)
second_word = s.join(second_word)
first_word = first_word.lower()
second_word = second_word.lower()
x=0
if len(first_word) == len(second_word):
for n in range(len(first_word)):
if first_word.count(first_word[n]) == second_word.count(first_word[n]):
x = x + 1
if x == len(first_word):
return True
return False
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(verify_anagrams("a", 'z'), bool), "Boolean!"
assert verify_anagrams("Kon", "no K") == True, "Gram of code"
assert verify_anagrams("Hello", "Ole Oh") == False, "Hello! Ole Oh!"
assert verify_anagrams("Kyoto", "Tokyo") == True, "The global warming crisis of 3002"
Oct. 20, 2016