1-liner speedy solution for Unix Match. Part 2 by Stensen - python coding challenges

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1-liner solution in Speedy category for Unix Match. Part 2 by Stensen

unix_match = lambda f, p: __import__('re').match(p
    .replace('.', r'\.')
    .replace('*', '.*')
    .replace('?', r'.{1}')
    .replace('[!]', r'\[\!\]')
    .replace('[!', '[^')
    .replace('[]', '[^.]'), f) is not None

Sept. 21, 2020

Comments:

sxy1054 on Oct. 23, 2020, 2:25 a.m.
<p>Nice</p>

Stensen on Oct. 23, 2020, 10:29 a.m.
<p>Thanks mate!</p>

Mine

0 %

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