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First solution in Clear category for Tricky String by kdim
def tricky_string(text: str) -> str:
s = k = 0
for i in range(len(text) - 6):
if (n := sum(i == j for i, j in zip(text[i:i + 7], "CheckIO"))) > s:
s, k = n, i
return text[:k] + "CheckIO" + text[k + 7:]
Nov. 11, 2023
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